Q. A vessel contains 110 g of water. The heat capacity of the vessel is equal to 10 g of water. The initial temperature of water in vessel in 10$℃$. If 220 g of hot water at 70$℃$ is poured in the vessel, the final temperature neglecting radiation loss will be
A) 70$℃$
B) $80℃$
C) $60℃$
D) $50℃$
Explanation
(d) Let final temperature of water be $\theta$
Heat taken = Heat given
$\ \ \ 100 \times 1 \times (\theta - 10) + 10(\theta - 10) = 220 \times 1(70 - \theta)$
$\Rightarrow$ $\theta = 48.8℃ = 50℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.