Q. A liquid of mass $M$ and specific heat $S$ is at a temperature $2t.$ If another liquid of thermal capacity 1.5 times, at a temperature of $\frac{t}{3}$ is added to it, the resultant temperature will be
A) $\frac{4}{3}t$
B) $t$
C) $\frac{t}{2}$
D) $\frac{2}{3}t$
Explanation
(b) $\theta_{mix} = \frac{m_{1}c_{1}\theta_{1} + m_{2}c_{2}\theta_{2}}{m_{1}c_{1} + m_{2}c_{2}} = \frac{m\ s(2t) + 1.5(m\ s) \times \frac{t}{3}}{m\ s + 1.5(m\ s)} = t$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.