Shown below are the black body radiation curves at temperatures $T_{1}$ and $T_{2}(T_{2} T_{1})$. Which of the following plots is correct

Question

Shown below are the black body radiation curves at temperatures $T_{1}$ and $T_{2}(T_{2} > T_{1})$. Which of the following plots is correct

Dr. Abubacker · Accepted Answer

(a) According to Wien’s displacement law
$\lambda_{m} \propto \frac{1}{T} \Rightarrow \lambda_{m_{2}} < \lambda_{m_{1}}\ \lbrack\because T_{1} < T_{2}\rbrack$
There fore $I - \lambda$ graph for $T_{2}$ has lesser wavelength $(\lambda_{m})$ and so curve for $T_{2}$ will shift towards left side

Q. Shown below are the black body radiation curves at temperatures $T_{1}$ and $T_{2}(T_{2} > T_{1})$. Which of the following plots is correct

Explanation

Reviewed by Dr. Abubacker

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