Q. A black body has maximum wavelength $\lambda_{m}$ at temperature $2000\ K$. Its corresponding wavelength at temperature $3000\ K$ will be
A) $\frac{3}{2}\lambda_{m}$
B) $\frac{2}{3}\lambda_{m}$
C) $\frac{4}{9}\lambda_{m}$
D) $\frac{9}{4}\lambda_{m}$
Explanation
(b) $\lambda_{m_{2}} = \frac{T_{1}}{T_{2}} \times \lambda_{m_{1}} = \frac{2000}{3000} \times \lambda_{m_{1}} = \frac{2}{3}\lambda_{m_{1}} = \frac{2}{3}\lambda_{m}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.