Q. The heat is flowing through a rod of length $50\ cm$ and area of cross-section $5cm^{2}$. Its ends are respectively at $25℃$ and $125℃$. The coefficient of thermal conductivity of the material of the rod is $0.092\ kcal/m \times s \times ℃$. The temperature gradient in the rod is
A) $2℃/cm$
B) $2℃/m$
C) $20℃/cm$
D) $20℃/m$
Explanation
(a) Temperature gradient $\frac{d\theta}{dx} = \frac{(125 - 25)℃}{50\ cm} = 2℃/cm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.