(c) Heat absorbed by water = Heat produced $mc\ \mathrm{\Delta}T = \frac{mgh}{J}$ $\mathrm{\Delta}\ T = \frac{gh}{Jc} = \ \frac{980 \times 500 \times 100}{4.2 \times 10^{7} \times 1\ } = \frac{900}{420} = 1.16℃$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.