Q. The absolute zero temperature in Fahrenheit scale is
A) $- 273^{o}F$
B) $- 32^{o}F$
C) $- 460^{o}F$
D) $- 132^{o}F$
Explanation
(c) $\frac{F - 32}{9} = \frac{K - 273}{5} \Rightarrow \frac{F - 32}{9} = \frac{0 - 273}{5}$
$\Rightarrow F = - {459.4}^{o}F = - 460{^\circ}F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.