Q. The rate of radiation of a black body at $0℃$ is $EJ/s$. The rate of radiation of this black body at $273℃$ will be
A) $16\ E$
B) $8\ E$
C) $4\ E$
D) $E$
Explanation
(a) $\frac{E_{1}}{E_{2}} = \left( \frac{T_{1}}{T_{2}} \right)^{4} \Rightarrow \frac{E}{E_{2}} = \left( \frac{273 + 0}{273 + 273} \right)^{4} \Rightarrow E_{2} = 16\ E$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.