Q. If temperature of an object is $140^{o}F,$ then its temperature in centigrade is
A) $105℃$
B) $32℃$
C) $140℃$
D) $60℃$
Explanation
(d) $\frac{C}{5} = \frac{F - 32}{9} \Rightarrow \frac{C}{5} = \frac{140 - 32}{9} \Rightarrow C = 60℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.