Q. A bubble of 8 mole of helium is submerged at a certain depth in water. The temperature of water increases by $30℃$. How much that is added approximately to helium during expansion
A) $4000\ J$
B) $3000\ J$
C) $3500\ J$
D) $5000\ J$
Explanation
(d) $n = 8\ mole,\ \mathrm{\Delta}t = 30℃$
$\theta = nc_{p}\mathrm{\Delta}t$
$\theta = 8 \times \frac{5}{2} \times 8.31 \times 30 = 5000$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.