According to Newton’s law of cooling, the rate of cooling is proportional to $(\mathrm{\Delta} heta)^{n}$, where $\mathrm{\Delta} heta$ is the temperature differences between the body and the surroundings and $n$ is equal to

Question

According to Newton’s law of cooling, the rate of cooling is proportional to $(\mathrm{\Delta}	heta)^{n}$, where $\mathrm{\Delta}	heta$ is the temperature differences between the body and the surroundings and $n$ is equal to

Dr. Abubacker · Accepted Answer

(d) According to Newton’s law of cooling the rate of loss of heat of a body is directly proportional to the difference in temperature of the body, $ie,$
$- \frac{dQ}{dt} \propto (\mathrm{\Delta}	heta)$ …(i)
Given, $- \frac{dQ}{dt} \propto (\mathrm{\Delta}	heta)^{n}$ …(ii)
Comparing Eqs. (i) and (ii), we get
$n$=1

Q. According to Newton’s law of cooling, the rate of cooling is proportional to $(\mathrm{\Delta}\theta)^{n}$, where $\mathrm{\Delta}\theta$ is the temperature differences between the body and the surroundings and $n$ is equal to

Explanation

Reviewed by Dr. Abubacker

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