Q. A gas undergoes an adiabatic change. Its specific heat in the process is
A) Zero
B) 1
C) $\infty$
D) None of these
Explanation
(a) $c = \frac{\mathrm{\Delta}Q}{m.\mathrm{\Delta}T} = \frac{\mathrm{\Delta}Q}{m \times 0} = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.