Q.
Six identical metallic rods are joined together in a pattern as shown in the figure. Points A and D are maintained at temperature $60℃$ and $240℃$. The temperature of the junction $B$ will be
A) $120℃$
B) $150℃$
C) $60℃$
D) $80℃$
Explanation
(a) $R = \frac{l}{KA}$
$\frac{T_{A} - T_{B}}{R} = \frac{T_{B} - T_{C}}{R} = \frac{T_{C} - T_{D}}{R}$
$60 - T_{B} = T_{B} - T_{C}$ …(i)
[image:11_image62.emf]
$60 - T_{B} = T_{C} - 240$ …(ii)
Solving (i) and (ii)
$T_{B} = 120℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.