Q. A body of area $1cm^{2}$ is heated to a temperature $1000K$. The amount of energy radiated by the body in $1\ s$ is (Stefan’s constant $\sigma = 5.67 \times 10^{- 8}Wm^{- 2}K^{- 4})$

A) 5.67 joule
B) 0.567 joule
C) 56.7 joule
D) 567 joule
Explanation

(a) Here, $A = 1cm^{2} = 10^{- 4}m^{2},T = 1000K,\ t = 1s$ and $\sigma = 5.67 \times 10^{- 8}Wm^{- 2}K^{- 4}$
According to Stefan-Boltzmann law, energy radiated by a body is
$E = \sigma AT^{4}t = 5.67 \times 10^{- 8} \times 10^{- 4} \times (1000)^{4} \times 1 = 5.67J$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.