Q. The relative humidity on a day when partial pressure of water vapour is 0.012$\times 10^{5}$ Pa at 12$℃$ is (Take vapour pressure of water at this temperature as 0.016$\times 10^{5}$ Pa)

A) 70%
B) 40%
C) 75%
D) 25%
Explanation

(c) Relative humidity at a given temperature (R )
$= \ \frac{Partial\ pressure\ of\ water\ vapour}{Vapour\ pressure\ of\ water}$
$= \frac{0.012 \times 10^{5}}{0.016 \times 10^{5}} = 0.75 = 75\%$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.