Q. Two spheres P and $Q$, of same colour having radii 8 cm and 2 cm are maintained at temperatures 127$℃$ and 527$℃$ respectively. The energy radiated by P and $Q$ is

A) 0.054
B) 0.0034
C) 1
D) 2
Explanation

(c) Total energy radiated from a body
$\mathcal{Q =}A\varepsilon\sigma T^{4}t$
$\Rightarrow$ $\mathcal{Q \propto}AT^{4} \propto r^{2}T^{4}$ $\ \ \ \ \ (\therefore A = 4\pi r^{2})$
$\Rightarrow$ $\frac{\mathcal{Q}_{P}}{\mathcal{Q}_{\mathcal{Q}}} = \left( \frac{r_{P}}{r_{\mathcal{Q}}} \right)^{2}\left( \frac{T_{\mathcal{P}}}{T_{\mathcal{Q}}} \right)^{4}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \left( \frac{8}{2} \right)^{2}\left\lbrack \frac{(273 + 127)}{(273 + 527)} \right\rbrack^{4} = 1$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.