Q. If at temperature $T_{1} = 1000K$, the wavelength is $1.4 \times 10^{- 6}m$, then at temperature the wavelength will be $2.8 \times 10^{- 6}m$

A) $2000K$
B) $500K$
C) $250K$
D) None of these
Explanation

(b) $\lambda_{m} \propto \frac{1}{T} \Rightarrow \lambda_{m_{1}}T_{1} = \lambda_{m_{2}}T_{2}$
$\Rightarrow T_{2} = \frac{\lambda_{m_{1}}T_{1}}{\lambda_{m_{2}}} = \frac{1.4 \times 10^{- 6} \times 1000}{2.8 \times 10^{- 6}} = 500\ K$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.