Q. Work done in converting one gram of ice at -10$℃$ into steam at 100$℃$ is
A) 3045 J
B) 6056 J
C) 721 J
D) 616 J
Explanation
(a) Work done $W = J\mathcal{Q}$
=$4.2(0.5 \times 10 + 1 \times 80 + 1 \times 100 + 1 \times 540)$
=3045 J
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.