A particular star (assuming it as a black body) has a surface temperature of about $5 imes 10^{4}K$. The wavelength in nanometers at which its radiation becomes maximum is $(b = 0.0029\ mK)$

Question

A particular star (assuming it as a black body) has a surface temperature of about $5 	imes 10^{4}K$. The wavelength in nanometers at which its radiation becomes maximum is $(b = 0.0029\ mK)$

Dr. Abubacker · Accepted Answer

(b) According to Wien’s displacement law
$\lambda_{m}T = b\ or\ \lambda_{m} = \frac{b}{T} = \frac{0.0029}{5 	imes 10^{4}} = 58 	imes 10^{- 9}m = 58nm$

Q. A particular star (assuming it as a black body) has a surface temperature of about $5 \times 10^{4}K$. The wavelength in nanometers at which its radiation becomes maximum is $(b = 0.0029\ mK)$

Explanation

Reviewed by Dr. Abubacker

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