Q. A constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at $0℃\ $and 100$℃\ $respectively. When the pressure reading is 60 cm of mercury, the temperature is
A) 25$℃$
B) 40$℃$
C) 12$℃$
D) 12.5$℃$
Explanation
(a) Here, $p_{0} = 50\ cm,\ p_{100} = 90\ cm,\ p_{t} = 60\ cm$
$t = \ \frac{p_{t} - p_{0}}{p_{100} - p_{0}} \times 100 = \frac{(60 - 50) \times 100}{(90 - 50)} = 25℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.