Q. The temperature of hot and cold end of a $20cm$ long rod in thermal steady state are at $100℃$ and $20℃$ respectively. Temperature at the centre of the rod is
A) $50℃$
B) $60℃$
C) $40℃$
D) $30℃$
Explanation
(b) Temperature gradient $= \frac{100 - 20}{20} = 4℃/cm$
Temperature of centre $= 100 - 4 \times 10 = 60℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.