A composite rod made of copper ($\alpha = 1.8 imes 10^{- 5}$ $K^{- 1}$) and steel ($\alpha = 1.2 imes 10^{- 5}$ $K^{- 1}$) is heated. Then

Question

A composite rod made of copper ($\alpha = 1.8 	imes 10^{- 5}$ $K^{- 1}$) and steel ($\alpha = 1.2 	imes 10^{- 5}$ $K^{- 1}$) is heated. Then

Dr. Abubacker · Accepted Answer

(a) If $l_{t}$ be length of rod at $t℃$ and $l_{0}$ at $0℃$, then
$l_{t} = l_{0}(1 + \alpha t)$
Where $\alpha$ is coefficient of linear expansion.
$\Rightarrow$ $l_{t}$ is proportional to $\alpha$. Since $\alpha_{c} > \alpha_{s}$, therefore copper will expand more, so rod bends with copper on convex side and steel on concave side.

Q. A composite rod made of copper ($\alpha = 1.8 \times 10^{- 5}$ $K^{- 1}$) and steel ($\alpha = 1.2 \times 10^{- 5}$ $K^{- 1}$) is heated. Then

Explanation

Reviewed by Dr. Abubacker

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