Q. A steel meter scale is to be ruled so that millimeter intervals are accurate within about $5 \times 10^{- 5}mm$ at a certain temperature. The maximum temperature variation allowable during the ruling is (Coefficient of linear expansion of steel $= 10 \times 10^{- 6}K^{- 1}$ )

A) $2℃$
B) $5℃$
C) $7℃$
D) $10℃$
Explanation

(b) As we know $\alpha = \frac{\mathrm{\Delta}L}{L_{0}\mathrm{\Delta}\theta} \Rightarrow \mathrm{\Delta}\theta = \frac{\mathrm{\Delta}L}{\alpha L_{0}} = \frac{5 \times 10^{- 5}}{10 \times 10^{- 6} \times 1} = 5℃$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.