Q. Steam at $100℃$ is passed into $1.1\ kg$ of water contained in a calorimeter of water equivalent to $0.02\ kg$ at $15℃$ till the temperature of the calorimeter and its contents rises to $80℃.$ The mass of the steam condensed in $kg$ is

A) $0.130$
B) $0.065$
C) $0.260$
D) $0.135$
Explanation

(a) Heat is lost by steam in two stages (i) for change of state from steam at $100℃$ to water at $100℃$ is $m \times 540$ (ii) to change water at $100℃$ to water at $80℃$ is $m \times 1 \times (100 - 80),$ where $m$ is the mass of steam condensed
Total heat lost by is $m \times 540 + m \times 20 = 560\ m(cals).$ Heat gained by calorimeter and its contents is $= (1.1 + 0.02) \times (80 - 15) = 1.12 \times 65\ cals$
Using Principle of calorimetery, Heat gained = heat lost
$\therefore 560\ m = 1.12 \times 65,\ m = 0.130\ g$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.