Q. 540 g of ice at 0$℃$ is mixed with 540 g of water at 80$℃$. The final temperature of the mixture is
A) 0$℃$
B) 40$℃$
C) 80$℃$
D) Less than 0$℃$
Explanation
(a) Heat absorbed by 540 g of ice at 0$℃$ to melt out = 540$\times 80$ cal. This is exactly what is available in 540 g of water at 80$℃$ to cool down to 0$℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.