Q. The maximum wavelength of radiation emitted at $2000K$ is $4\mu m$. What will be the maximum wavelength of radiation emitted at $2400\ K$
A) $3.33\mu m$
B) $0.66\mu m$
C) $1\mu m$
D) $1m$
Explanation
(a) $\therefore\frac{\lambda_{m_{2}}}{\lambda_{m_{1}}} = \frac{T_{1}}{T_{2}} \Rightarrow \lambda_{m_{2}} = \frac{2000}{2400} \times 4 = 3.33\ \mu m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.