(c) $\frac{E_{2}}{E_{1}} = \left( \frac{T_{2}}{T_{1}} \right)^{4} \Rightarrow \frac{E_{2}}{20} = \left( \frac{2T}{T} \right)^{4} = 16 \Rightarrow E_{2} = 320\ kcal/m^{2}\min$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.