Q. The temperature gradient in a rod of $0.5\ m$ long is $80℃/m$. If the temperature of hotter end of the rod is $30℃$, then the temperature of the cooler end is
A) $40℃$
B) $- 10℃$
C) $10℃$
D) $0℃$
Explanation
(b) $\frac{\theta_{1} - \theta_{2}}{l} = 80 \Rightarrow \frac{30 - \theta_{2}}{0.5} = 80 \Rightarrow \theta_{2} = - 10℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.