Q. One end of a metal rod of length 1.0 m and area of cross-section 100${cm}^{2}$ is maintained at 100 $℃$. If the other end of the rod is maintained at 0$℃$, the quantity of heat transmitted through the rod per minute is (coefficient of thermal conductivity of material of rod =100W/m-K)
A) $3 \times 10^{3}$ J
B) $6 \times 10^{3}$ J
C) $9 \times 10^{3}$ J
D) $12 \times 10^{3}$ J
Explanation
(b) Heat current, $\frac{\mathcal{Q}}{t} = \ \frac{KA(\theta_{1} - \theta_{1})}{l}$
= $\frac{100 \times 100 \times 10^{- 4}(100 - 0)}{1}$
$\Rightarrow$ $\frac{\mathcal{Q}}{t}$ = 100J/s=$6 \times 10^{3}$ J/min
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.