Q. Hot water kept in a beaker placed in a room cools from $70℃$ to $60℃$ in $4\ minutes$. The time taken by it to cool from $69℃$ to $59℃$ will be

A) The same 4 minutes
B) More than 4 minutes
C) Less than 4 minutes
D) We cannot say definitely
Explanation

(b) Rate of cooling $= \frac{- d\theta}{dt} \propto \left( \frac{\theta_{1} + \theta_{2}}{2} - \theta_{0} \right)$
In second case average temperature will be less hence rate of cooling will be less. Therefore time taken will be more than 4 minutes

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.