Q. The weight of a person is $60\ kg.$ If he gets $10^{5}$ calories heat through food and the efficiency of his body is 28%, then upto how much height he can climb (approximately)
A) $100\ m$
B) $200\ m$
C) $400\ m$
D) $1000\ m$
Explanation
(b) Suppose person climbs upto height $h,$ then by using
$W = JQ \Rightarrow mgh = JQ$
$\Rightarrow 60 \times 9.8 \times h = 4.2 \times \left( 10^{5} \times \frac{28}{100} \right) \Rightarrow h = 200\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.