Q. Temperature of a black body increases from $327℃$ to $927℃$, the initial energy possessed is $2KJ$, what is its final energy
A) $32\ KJ$
B) $320\ KJ$
C) $1200\ KJ$
D) None of these
Explanation
(a) $\frac{Q_{2}}{Q_{1}} = \left( \frac{T_{2}}{T_{1}} \right)^{4} = \left( \frac{273 + 927}{273 + 327} \right)^{4} = \left( \frac{1200}{600} \right)^{4} = 16$
$\Rightarrow Q_{2} = 32\ KJ$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.