(a) Here, $t_{1} = 0℃ = 273K,\ t_{2} = 473K$
$\gamma_{r} = 0.18\ \times 10^{- 3}℃^{- 1};d_{1} = 13.6\ g/cc$
$d\ = \frac{d_{1}\ }{1 + \gamma_{r}(\mathrm{\Delta}T)}$
= $\frac{13.6}{1 + 0.18 \times 10^{- 3} \times (473 - 273)}$
$d_{2} = \frac{13.6}{1.036} = 13.127g/cc$