(b) $Y = \frac{FL}{Al}$ where $Y$ is Young’s modulus, $A$ is area
$\Rightarrow F = \frac{YAl}{L}$ $\ldots(i)$
From the formula for linear expansion
$\alpha = \frac{l}{L \times 100}$ $\ldots(ii)$
According to the condition the bar should not bend or expand
Now from equations (i) and (ii)
$F = YA \times 100\alpha$
Hence, force is independent of length $L$