Q. A rod of silver at $0℃$ is heated to $100℃$. It’s length is increased by $0.19\ cm.$ Coefficient of cubical expansion of the silver rod is
A) $5.7 \times 10^{- 5}/℃$
B) $0.63 \times 10^{- 5}/℃$
C) $1.9 \times 10^{- 5}/℃$
D) $16.1 \times 10^{- 5}/℃$
Explanation
(a) $\alpha = \frac{\mathrm{\Delta}L}{L_{0}(\mathrm{\Delta}\theta)} = \frac{0.19}{100(100 - 0)} = 1.9 \times 10^{- 5}/℃$
Now $\gamma = 3\alpha = 3 \times 1.9 \times 10^{- 5}/℃ = 5.7 \times 10^{- 5}/℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.