Q. A faulty thermometer has its lower fixed point marked as $- 10℃$ and upper fixed point marked as $110^{o}.$ If the temperature of the body shown in this scale is $62^{o},$ the temperature shown on the Celsius scale is
A) $72℃$
B) $82℃$
C) $60℃$
D) $42℃$
Explanation
(c) $\frac{X - L}{U - L} = \frac{C}{100} \Rightarrow \frac{62 - ( - 10)}{110 - ( - 10)} = \frac{C}{100}\ \ (C = 60℃)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.