Q. When the amount of work done is $333\ cal$ and change in internal energy is $167\ cal,$ then the heat supplied is
A) $166\ cal$
B) $333\ cal$
C) $500\ cal$
D) $400\ cal$
Explanation
(c) $\mathrm{\Delta}Q = \mathrm{\Delta}U + \mathrm{\Delta}W = 167 + 333 = 500\ cal$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.