Q. Carnot cycle (reversible) of a gas represented by a Pressure-Volume curve is shown in the diagram Consider the following statements I. Area $ABCD =$ Work done on the gas II. Area $ABCD =$ Net heat absorbed III. Change in the internal energy in cycle = 0 Which of these are correct

A) I only
B) II only
C) II and III
D) I, II and III
Explanation

(c) Work done by the gas (as cyclic process is clockwise) $\therefore\mathrm{\Delta}W =$ Area $ABCD$
So from the first law of thermodynamics $\mathrm{\Delta}Q$ (net heat absorbed) $= \mathrm{\Delta}W =$Area$\ ABCD$
As change in internal energy in cycle $\mathrm{\Delta}U = 0$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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