(c) Work done by the gas (as cyclic process is clockwise) $\therefore\mathrm{\Delta}W =$ Area $ABCD$
So from the first law of thermodynamics $\mathrm{\Delta}Q$ (net heat absorbed) $= \mathrm{\Delta}W =$Area$\ ABCD$
As change in internal energy in cycle $\mathrm{\Delta}U = 0$