Q. A gas expands $0.25m^{3}$ at constant pressure $10^{3}N/m^{2}$, the work done is
A) $2.5\ ergs$
B) $250\ J$
C) $250\ W$
D) $250\ N$
Explanation
(b) $\mathrm{\Delta}W = P\mathrm{\Delta}V = 10^{3} \times 0.25 = 250\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.