A container having 1 mole of a gas at a temperature $27℃$ has a movable piston which maintains at constant pressure in container of 1 atm. The gas is compressed until temperature becomes $127℃$. The work done is $(C_{p}for\ gas\ is\ 7.03cal/mol - K)$

Question

Dr. Abubacker · Accepted Answer

(b) Work done at constant pressure is
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ W = p\ \mathrm{\Delta}V = nR\ \mathrm{\Delta}T$
Where p is presure, $\mathrm{\Delta}V$ the volume change, R the gas constant, $\mathrm{\Delta}T$ the change in temperature and n the number of moles.
Given, n=1, $T_{2} = 127℃ = 400K,$
$T_{1} = 27℃ = 300K,\ \ \ \ \ \ \ \ R = 8.14\ J/mol - K$
$	herefore W = 1 	imes 8.14 	imes (400 - 300)$
W=814 J

Q. A container having 1 mole of a gas at a temperature $27℃$ has a movable piston which maintains at constant pressure in container of 1 atm. The gas is compressed until temperature becomes $127℃$. The work done is $(C_{p}for\ gas\ is\ 7.03cal/mol - K)$

Explanation

Reviewed by Dr. Abubacker

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