Q. In the cyclic process shown in the figure, the work done by the gas in one cycle is
A) $28\ P_{1}V_{1}$
B) $14\ P_{1}V_{1}$
C) $18\ P_{1}V_{1}$
D) $9\ P_{1}V_{1}$
Explanation
(d) Work done = Area under curve $= \frac{6P_{1} \times 3V_{1}}{2} = 9\ P_{1}V_{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.