Q. An ideal heat engine works between temperatures $T_{1} = 500K\ and\ T_{2} = 375K.$ If the engine absorbs 600 J of heat from the source, then the amount of heat released to the sink is

A) 450 J
B) 600 J
C) 45 J
D) 500 J
Explanation

(a) For heat engine, $\frac{Q_{2}}{Q_{1}} = \frac{T_{2}}{T_{1}}$
$\Rightarrow \ \ \ \ \ \ Q_{2} = \frac{T_{2}Q_{1}}{T_{1}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{375 \times 600}{500} = 450\ J$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Thermodynamics MCQs