Q. A Carnot engine has the same efficiency between 800 K to 500 K and $x$K to 600 K. The value of $x$ is
A) 100 K
B) 960 K
C) 846 K
D) 754 K
Explanation
(b) $\eta = 1 - \frac{T_{2}}{T_{1}} = 1 - \frac{500}{800} = 1 - \frac{600}{x}$
$\therefore\ \ \frac{3}{8} = 1 - \frac{600}{x}$
$\frac{600}{x} = 1 - \frac{3}{8} = \frac{5}{8}$
$5x = 4800,\ x = \frac{4800}{5} = 960\ K$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.