Q. If the heat 110 J is added to a gaseous system and it acquires internal energy of 40 J, then the amount of internal work done is
A) 40 J
B) 70 J
C) 150 J
D) 110 J
Explanation
(b) Here, $dQ = 110\ J,\ dU = 40\ J,\ dW = ?$
From $dQ = dU + dW$
$dW = dQ - dU = 110 - 40 = 70\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.