Q. If $C_{V} = 4.96cal/mole\ K$, then increase in internal energy when temperature of 2 moles of this gas is increased from $340\ K$ to $342\ K$
A) $27.80\ cal$
B) $19.84\ cal$
C) $13.90\ cal$
D) $9.92\ cal$
Explanation
(b) $\mathrm{\Delta}U = \mu C_{V}\mathrm{\Delta}T = 2 \times 4.96 \times (342 - 340) = 19.84\ cal$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.