Q. In an adiabatic process $90J$ of work is done on the gas. The change in internal energy of the gas is
A) $- 90\ J$
B) $+ 90\ J$
C) $0\ J$
D) Depends on initial temperature
Explanation
(b) For adiabatic process $\mathrm{\Delta}Q = 0$
From $\mathrm{\Delta}Q = \mathrm{\Delta}U + \mathrm{\Delta}W \Rightarrow 0 = \mathrm{\Delta}U - 90 \Rightarrow \mathrm{\Delta}U = + 90J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.