Q.
$p - V$ diagram of an ideal gas is as shown in figue. Work done by the gas in the process $ABCD$ is
A) $4\ p\ V_{0}$
B) $2\ p_{0}\ V_{0}$
C) $3\ p_{0}\ V_{0}$
D) $p_{0}\ V_{0}$
Explanation
(c) $W_{AB} = - p_{0}V_{0}$
$W_{BC} = 0$
$W_{CD} = 4\ p_{0}V_{0}$
$W_{ABCD} = W_{AB} + W_{BC} + W_{CD}$
$= - p_{0}V_{0} + 0 + 4p_{0}V_{0} = 3p_{0}V_{0}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.