(c) $\mathrm{\Delta}C = \mathrm{\Delta}U + \mathrm{\Delta}W\ \because\ \mathrm{\Delta}W = 0 \Rightarrow \mathrm{\Delta}Q = \mathrm{\Delta}U = \frac{f}{2}\mu R\mathrm{\Delta}T$ $= \frac{3}{2} \times 2R(373 - 273) = 300R$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.