A Carnot engine absorbs an amount $Q$ of heat from a reservoir at an absolute temperature $T$ and rejects heat to a sink at a temperature $T$ and rejects heat to a sink at a temperature of $T$/3. The amount of heat rejected is

Question

Dr. Abubacker · Accepted Answer

(b) The efficiency $(\eta)$ of Carnot engine is
$\ \ \ \ \ \eta = \frac{\Delta W}{\Delta Q_{H}} = 1 - \frac{Q_{reject}}{Q_{taken}} = 1 - \frac{T_{sink}}{T_{source}}$
$\Rightarrow \ \ \ \ \ \frac{Q_{reject}}{Q_{taken}} = \frac{T_{sink}}{T_{source}}$
$\Rightarrow \ \ \ \ \ \ Q_{reject} = \frac{T/3}{T}\ \ Q = \frac{Q}{3}\ \ $

Q. A Carnot engine absorbs an amount $Q$ of heat from a reservoir at an absolute temperature $T$ and rejects heat to a sink at a temperature $T$ and rejects heat to a sink at a temperature of $T$/3. The amount of heat rejected is

Explanation

Reviewed by Dr. Abubacker

Want more practice?