Explanation

(c) In this process, p and V changes but T=constant ie, change in temperature $\mathrm{\Delta}T = 0$
Boyle’s law is obeyed ie, pV=constant
$\Rightarrow \ \ \ \ p_{1}V_{1} = p_{2}V_{2}$
According to pV=constant, graph between p and V is a part of rectangular hyperbola. Therefore, option(c) is correct.